How is s(n) defined when n has only 1 digit? Is it n itself?
So is N(1) just equal to 1 since s(1)=1 is the smallest number satisfying s(n)=1*n?
Problem 805
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Don't start begging others to give partial answers to problems
Don't ask for hints how to solve a problem
Don't start a new topic for a problem if there already exists one
See also the topics:
Don't post any spoilers
Comments, questions and clarifications about PE problems.
- neverforget
- Posts: 88
- Joined: Sat Sep 16, 2006 10:10 pm
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radeye
- Posts: 9
- Joined: Mon Oct 30, 2017 7:13 pm
Re: Problem 805
In problem 805, the $T(M)$ uses an upper-case $M$, while the later reference to the function parameter uses a lower-case $m$. Indeed this whole problem has a really interesting combination of upper- and lower-case identifiers.
- bruce_love
- Administrator
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Re: Problem 805
Thanks for that radeye - it has been fixed. Changing the later reference $m$ to $M$.
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Dusterbraut
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Re: Problem 805 - another question
Sorry,
I don't understand English very well.
My question is:
What are "... all ordered pairs of coprime positive integers not exceeding $M$"?
Do you mean all pairs (u,v) with 1 <= u < v <= M with gcd (u,v) = 1 ?
Thanks a lot for answering my stupid little question.
I don't understand English very well.
My question is:
What are "... all ordered pairs of coprime positive integers not exceeding $M$"?
Do you mean all pairs (u,v) with 1 <= u < v <= M with gcd (u,v) = 1 ?
Thanks a lot for answering my stupid little question.
- neverforget
- Posts: 88
- Joined: Sat Sep 16, 2006 10:10 pm
Re: Problem 805
There's no restriction that $u<v$.
It's all $1\leq u\leq M$ and $1\leq v\leq M$ where $\gcd(u,v)=1$
It's all $1\leq u\leq M$ and $1\leq v\leq M$ where $\gcd(u,v)=1$
