Problem 556

[v6ph1]

Problem 556 (View Problem)
The Factorization of 1+3i seams to be wrong:
It should be (1+i)*(2+i)

[mpiotte]

Problem 556 (View Problem)
The Factorization of 1+3i seams to be wrong:
It should be (1+i)*(2+i)

Thanks, corrected.

[Swistakk]

Problem 556 (View Problem)
The Factorization of 1+3i seams to be wrong:
It should be (1+i)*(2+i)

Thanks, corrected.

Well, not really...

[echip]

Problem 556 (View Problem)
The Factorization of 1+3i seams to be wrong:
It should be (1+i)*(2+i)

Thanks, corrected.

You say it's corrected, But I see (1+i)*(1+2*i)

[skoczian]

Problem 556 (View Problem)
The Factorization of 1+3i seams to be wrong:
It should be (1+i)*(2+i)

Thanks, corrected.

This factorization occurs twice in the problem text. Only once it's corrected:

A Gaussian integer can be uniquely factored as the product of a unit and proper Gaussian primes.
For example 2 = -i(1 + i)² and 1 + 3i = (1 + i)(2 + i).

Here it's correct.
And in the next paragraph:

For example f(10) = 7 because 1, 1 + i, 1 + 2i, 1 + 3i = (1 + i)(1 + 2i), ...

Still wrong.

[RobertStanforth]

Thank you everyone for flagging this. The second occurrence has now been corrected to read (1+3i)=(1+i)(2+i).