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Problem 963

Posted: Mon Oct 06, 2025 2:14 am
by byhill
Presumably, a player loses if they don't have any available moves to play? I don't think this is mentioned explicitly.

Re: Problem 963

Posted: Mon Oct 06, 2025 7:58 pm
by philiplu
Correct. That's pretty standard with combinatorial games - the winner is the last person to make a move; the loser is the first person who is unable to move for whatever reason. The alternative to this "normal play condition" is a misère game, where the first player unable to move wins, but that's less common. I don't think there's been a PE problem in CGT operating by misère rules, but I could be forgetting a case.

Re: Problem 963

Posted: Tue Oct 07, 2025 5:34 am
by phatmo
Maybe https://projecteuler.net/problem=400 is one with misère game ?

Re: Problem 963

Posted: Sun Oct 19, 2025 11:19 am
by Momotaro
Is it permissible to remove the leading 1 from 101 to make it 1?
I sensed two possible interpretations from the statement “Leading zeros are not allowed in any ternary expansion”:
* Case 1: Since leading 0s are not allowed, transitioning from 101 to 01 is not permitted.
* Case 2: Since leading 0s are not allowed, removing the leading 1 from 101 causes an immediate transition to 1.

Re: Problem 963

Posted: Sun Oct 19, 2025 4:31 pm
by amic
Yes, it is possible to remove such a 1. It will do 101 → 1.