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Problem 243

Posted: Mon May 04, 2009 6:55 am
by chrisb555
Hi,

Could someone clarify for me what is meant by "ratio of its proper fractions that are resilient"?
What I understand to be the ratio of the resilient fractions for d=12 is :
(1/12):(5/12):(7/12):(11/12)
and I calculate this to be 144/385. So clearly my understanding is different to yours.
Could you clarify?

Thanks,
Chris

Re: Problem 243

Posted: Mon May 04, 2009 7:30 am
by ed_r
R(d) is the number of resilient proper fractions, divided by d-1.

"Proportion" would have been a better word than "ratio".

Re: Problem 243

Posted: Tue May 05, 2009 1:01 am
by chrisb555
Thanks Ed - that's very clear :-)

Re: Problem 243

Posted: Mon Feb 23, 2015 1:04 am
by Oliver1978
So primes always give 1?

Re: Problem 243

Posted: Mon Feb 23, 2015 1:17 am
by Georg
Yes.

Re: Problem 243

Posted: Sun Nov 25, 2018 10:32 am
by frodenburg
How come R(12) is the lowest resilient denominator below 40% and that there is ANOTHER lowest denominator below 16%?
What is meant with minimal and what should I be looking for? Is my english the issue?

Re: Problem 243

Posted: Sun Nov 25, 2018 12:37 pm
by Animus
You can find a lower resilent fraction for higher denominators, the question is how big the denominator must get in order to get the resilent fraction below the given treshold for the very first time. That's no contradiction.

PS: Your nickname sounds german. If english is an issue and german is fine, you can PM me "auf Deutsch".

Re: Problem 243

Posted: Tue Nov 27, 2018 2:45 pm
by frodenburg
So in this case of lowest below 4/10 means that the 4 is fixed and the lowest x of D(x) with numerator 4 is to be found?
I'll try that and see.

Re: Problem 243

Posted: Tue Nov 27, 2018 2:47 pm
by frodenburg
By the way, I am Dutch, so German does not really help :-(
Thanks for your explanation though, I give it a try to see if I understood.