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Re: Could anyone confirm a value for problem 213?
Posted: Tue Nov 18, 2008 7:14 pm
by Tommy137
4 1 4.778
This is correct.
4 2 5.338
4 3 5.639
These two are not

Re: Could anyone confirm a value for problem 213?
Posted: Tue Nov 18, 2008 10:10 pm
by LarryC
Thanks for the reply!
Would you mind giving me those case values? I have more values I wish to check...
Re: Could anyone confirm a value for problem 213?
Posted: Wed Nov 19, 2008 11:05 am
by Tommy137
lster wrote:Thanks for the reply!
Would you mind giving me those case values? I have more values I wish to check...
PM'ed you.
Re: Could anyone confirm a value for problem 213?
Posted: Wed Nov 19, 2008 2:17 pm
by LarryC
Thanks Tommy! As it happens, though, I've already completed it.
I think that is probably the second hardest Project Euler (for me). The hardest not being 198, however!

Re: Could anyone confirm a value for problem 213?
Posted: Wed Nov 19, 2008 2:46 pm
by Tommy137
lster wrote:Thanks Tommy! As it happens, though, I've already completed it.

I saw it a few minutes after I send you the values
lster wrote:I think that is probably the second hardest Project Euler (for me). The hardest not being 198, however!

I agree with 198 not being the hardest... I still have no idea how to even approach
Problem 208 (
View Problem)

Re: Could anyone confirm a value for problem 213?
Posted: Wed Nov 19, 2008 2:51 pm
by quilan
Unrelated, but am I one of the only ones that thought 198 really wasn't all that difficult? Especially considering we've had another earlier problem that practically gave away one method of solving it?
Re: Could anyone confirm a value for problem 213?
Posted: Wed Nov 19, 2008 3:12 pm
by hk
Yes but many did not solve that earlier problem in one of the intended ways. That's no problem if one studies afterwards how it should have been solved to be prepared for a follow up. Obviously they failed to do so.
Re: Could anyone confirm a value for problem 213?
Posted: Wed Nov 19, 2008 3:33 pm
by LarryC
Yay! I'm a 100%-er again after a long gap!
Anyway, 198 definitely was a tough one but this one I just failed to wrap my brain around so to speak. Most of the other probability questions have been fine but this one was extremely tough for me!

Re: Could anyone confirm a value for problem 213?
Posted: Sat Nov 22, 2008 7:55 am
by Ikcelaks
Most of the other probability questions have been fine but this one was extremely tough for me!
I loved this problem in part because, while it didn't require any sort of advanced knowledge, it really tested your understanding of the fundamentals of probabilites and expected values.
Unrelated, but am I one of the only ones that thought 198 really wasn't all that difficult? Especially considering we've had another earlier problem that practically gave away one method of solving it?
For that very reason, 198 was essentially trivial for me. Meanwhile, 202, which many have solved, was extraordinarily elusive. Clearly, there is no such thing as a toughest problem on any remotely absolute scale.
Re: Could anyone confirm a value for problem 213?
Posted: Sat Nov 22, 2008 8:26 am
by quilan
I don't know... 177 & 184 seem to me the hardest problems that have been on this site bar none.
Re: fleas
Posted: Tue Nov 25, 2008 8:23 am
by axelbrz
Hi, are these expected values correct for a 4x4 matrix?:
Bell 1: 4.777778
Bell 2: 1.941406
Bell 3: 3.505002
Bell 4: 2.589931
Bell 5: 3.114868
Thanks!
Re: fleas
Posted: Tue Nov 25, 2008 11:45 am
by Tommy137
axelbrz wrote:Hi, are these expected values correct for a 4x4 matrix?:
Bell 1: 4.777778
Bell 2: 1.941406
Bell 3: 3.505002
Bell 4: 2.589931
Bell 5: 3.114868
Thanks!
Only the first value is correct.
Re: Problem 213
Posted: Thu Feb 12, 2009 8:02 pm
by viv_ban
As pointed earlier, the expected number of empty square after one toll is equal to 1 in case of 2X2 grid. Will it remain the same forever(i.e. remains 1 irrespective of number of tolls).
Re: Problem 213
Posted: Thu Feb 12, 2009 8:12 pm
by daniel.is.fischer
Yes.
Re: Problem 213
Posted: Thu Feb 12, 2009 8:57 pm
by viv_ban
I am sure that my algorithm is correct but I am still not getting the right answer.
Can anybody please tell me if I am correct for the following values:
expected empty cells for 4X4 after 2 tolls are 4.86548889746 and after 50 tolls are 4.93827160494
in case of 20X20 after 50 tolls expected empty cells are 126.37819102.
thanks.
Re: Problem 213
Posted: Thu Feb 12, 2009 9:02 pm
by daniel.is.fischer
No, all those are wrong.
Re: Problem 213
Posted: Thu Apr 23, 2009 3:53 am
by Assato
Wow, I must be doing something seriously wrong then... my simulations give:
<deleted - ed_r>
Re: Problem 213
Posted: Thu Apr 23, 2009 7:29 am
by ed_r
I've deleted your simulation results, which are potential spoilers. Seems your simulation works just fine.
Re: Problem 213
Posted: Thu Apr 23, 2009 10:57 pm
by Assato
Oh, sorry, I posted because I was about sure they were wrong... I read in the last page it was close to 147, but didn't realize that was a 20x20 simulation!
Re: Problem 213
Posted: Thu Apr 23, 2009 11:29 pm
by quilan
Assato wrote:Oh, sorry, I posted because I was about sure they were wrong... I read in the last page it was close to 147, but didn't realize that was a 20x20 simulation!
Yeah, I was being particularly tricky...