Re: Problem 239
Posted: Sat Dec 17, 2011 2:09 pm
I think there are more things you can do yourself first.szymczak wrote:If I make a nice write up of my solution (formula and explanation) will you, or anyone else who has solved the problem take a PM and look at it? At least to tell me where (and not how) my reasoning went wrong.
If you add all your probabilities for 0 to 25 out of place, is the sum equal to 1?
Is the expected value for the number of out-of-place primes equal to the obvious? (I found it easier to count in-place primes.)
Are all your probabilities multiples of (1/n!)? This might be easier to check with a lower n than 100, say 5.