## Problem 600

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RichardDL
Posts: 1
Joined: Sat Mar 16, 2019 3:56 pm

### Problem 600

Hi, I've written something that seems correct, H(12) = 100, but H(100) = 52788 not 31248 as stated. I've looked at all my results to see if they conform: They draw as hexagons; numerical checks on on the side-lengths are correct; perimeters <= 100. Are they congruent? I've eliminated some/all congruency and almost all results have different sets of side-lengths so are not even candidates for congruency. I've been round this lots of times all I can think is there's an implied rule I've not seen, or the stated answer is wrong (v. unlikely). Ideally someone would look at my 5k2 results (.csv) and point out some that don't conform. (I hope this is within the rules here, don't want help on algorithm/solution.)

Perim, a, b, c, d, e, f
...
18, 3, 3, 3, 3, 3, 3
18, 4, 2, 4, 2, 4, 2
18, 4, 3, 2, 4, 3, 2
18, 4, 4, 1, 4, 4, 1
18, 5, 1, 4, 3, 3, 2
18, 5, 1, 5, 1, 5, 1
18, 5, 2, 2, 5, 2, 2
18, 5, 2, 3, 3, 4, 1
18, 5, 3, 1, 5, 3, 1
18, 6, 1, 3, 4, 3, 1
18, 6, 2, 1, 6, 2, 1
18, 7, 1, 1, 7, 1, 1
...
jaap
Posts: 553
Joined: Tue Mar 25, 2008 3:57 pm
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### Re: Problem 600

RichardDL wrote: Sat Mar 16, 2019 4:13 pm 18, 5, 1, 4, 3, 3, 2
18, 5, 2, 3, 3, 4, 1
Hexagons that are mirror images of one another are congruent.