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Problem 699

Posted: Mon Jan 27, 2020 1:24 pm
by pjt33
There's an error in the problem statement. It currently says
the denominator is a power of 3 i.e. $b=3^k, k>0$.
It should say
the denominator is a power of 3 other than 1, i.e. $b=3^k, k>0$.
(The other possible correction, $>$ to $\ge$, doesn't match up with the test cases).