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Comments, questions and clarifications about PE problems.
- Posts: 39
- Joined: Mon Oct 06, 2008 6:14 pm
There's an error in the problem statement. It currently says
the denominator is a power of 3 i.e. $b=3^k, k>0$.
It should say
the denominator is a power of 3 other than 1, i.e. $b=3^k, k>0$.
(The other possible correction, $>$ to $\ge$, doesn't match up with the test cases).