Problem 600

A place to air possible concerns or difficulties in understanding ProjectEuler problems. This forum is not meant to publish solutions. This forum is NOT meant to discuss solution methods or giving hints how a problem can be solved.
Forum rules
As your posts will be visible to the general public you
are requested to be thoughtful in not posting anything
that might explicitly give away how to solve a particular problem.

This forum is NOT meant to discuss solution methods for a problem.

In particular don't post any code fragments or results.

Don't start begging others to give partial answers to problems

Don't ask for hints how to solve a problem

Don't start a new topic for a problem if there already exists one


See also the topics:
Don't post any spoilers
Comments, questions and clarifications about PE problems.
Post Reply
RichardDL
Posts: 1
Joined: Sat Mar 16, 2019 3:56 pm

Problem 600

Post by RichardDL »

Hi, I've written something that seems correct, H(12) = 100, but H(100) = 52788 not 31248 as stated. I've looked at all my results to see if they conform: They draw as hexagons; numerical checks on on the side-lengths are correct; perimeters <= 100. Are they congruent? I've eliminated some/all congruency and almost all results have different sets of side-lengths so are not even candidates for congruency. I've been round this lots of times all I can think is there's an implied rule I've not seen, or the stated answer is wrong (v. unlikely). Ideally someone would look at my 5k2 results (.csv) and point out some that don't conform. (I hope this is within the rules here, don't want help on algorithm/solution.)

Perim, a, b, c, d, e, f
...
18, 3, 3, 3, 3, 3, 3
18, 4, 2, 4, 2, 4, 2
18, 4, 3, 2, 4, 3, 2
18, 4, 4, 1, 4, 4, 1
18, 5, 1, 4, 3, 3, 2
18, 5, 1, 5, 1, 5, 1
18, 5, 2, 2, 5, 2, 2
18, 5, 2, 3, 3, 4, 1
18, 5, 3, 1, 5, 3, 1
18, 6, 1, 3, 4, 3, 1
18, 6, 2, 1, 6, 2, 1
18, 7, 1, 1, 7, 1, 1
...
User avatar
jaap
Posts: 553
Joined: Tue Mar 25, 2008 3:57 pm
Contact:

Re: Problem 600

Post by jaap »

RichardDL wrote: Sat Mar 16, 2019 4:13 pm 18, 5, 1, 4, 3, 3, 2
18, 5, 2, 3, 3, 4, 1
Hexagons that are mirror images of one another are congruent.
Post Reply