## Problem 032

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Comments, questions and clarifications about PE problems.

### Problem 032

Hello.

I think I've found the solution to problem 32, but projecteuler.net rejects it.

Problem 32 asks:

"Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital. "

I think these are the products:

[edit]Removed correct solution set[/edit]

and the sum of the products is _____, but it does not seem to be the answer.

What I'm doing wrong?

Thanks

I think I've found the solution to problem 32, but projecteuler.net rejects it.

Problem 32 asks:

"Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital. "

I think these are the products:

[edit]Removed correct solution set[/edit]

and the sum of the products is _____, but it does not seem to be the answer.

What I'm doing wrong?

Thanks

- euler
- Administrator
**Posts:**3067**Joined:**Sun Mar 05, 2006 4:49 pm**Location:**Cheshire, England-
**Contact:**

### Re: Problem 32

I've edited your post to remove the list, as it is correct. Remember, the word product means the answer you get from multiplying. You might find the hint in the problem statement helpful.

*impudens simia et macrologus profundus fabulae*

### Re: Problem 32

Am I getting it right that multiplicand/multiplier/product should have in total exactly

**nine**digits?- daniel.is.fischer
**Posts:**2400**Joined:**Sun Sep 02, 2007 10:15 pm**Location:**Bremen, Germany

### Re: Problem 32

Yes.

Il faut respecter la montagne -- c'est pourquoi les gypaètes sont là.

### Problem 32

can anyone explain me what does "pandigital" mean?

thanks

thanks

### Re: Problem 32

**Problem 41**(View Problem): We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once.

- euler
- Administrator
**Posts:**3067**Joined:**Sun Mar 05, 2006 4:49 pm**Location:**Cheshire, England-
**Contact:**

### Re: Problem 32

Good question, marco6. I hadn't realised that a definition was missing from that question. I've added the same definition from problem 41 (thanks, Georg) as an introduction to the problem.

**Problem 32**(View Problem)*impudens simia et macrologus profundus fabulae*

### Re: Problem 032

Mods: A very small typo in the last word of the first paragraph - "pandigitial".

- daniel.is.fischer
**Posts:**2400**Joined:**Sun Sep 02, 2007 10:15 pm**Location:**Bremen, Germany

### Re: Problem 032

Thanks - fixed.

Il faut respecter la montagne -- c'est pourquoi les gypaètes sont là.

### Re: Problem 032

Hello,

I think that I have found correct solution but ProjectEuler rejects it so I have a question:

For example is 39 x 186 = 7254 and 186 x 39 = 7254 counted as one or two different pandigital identities?

I think that I have found correct solution but ProjectEuler rejects it so I have a question:

For example is 39 x 186 = 7254 and 186 x 39 = 7254 counted as one or two different pandigital identities?

### Re: Problem 032

One. The problem clearly states:

Note that this is even stricter than just swapping the two factors.HINT: Some products can be obtained in more than one way so be sure to only include it once in your sum.

_{Jaap's Puzzle Page}

### Re: Problem 032

Thanks, I omitted the word "once" while I was reading

### Re: Problem 032

Could someone explain to me what this problem is referring to by "identity"? I know it's meaning in other contexts, not this one.

Thanks in advance!

Thanks in advance!

- rayfil
- Administrator
**Posts:**1401**Joined:**Sun Mar 26, 2006 4:30 am**Location:**Ontario, Canada-
**Contact:**

### Re: Problem 032

When you have an equal sign (=), it means that both sides must be considered identical. Thus, 39 × 186 can be considered an identity of 7254. Similarly 78 x 93, 31 x 234 and 13 x 18 x 31 would also be considered identities of 7254 among many others.

When you assume something, you risk being wrong half the time.

### Re: Problem 032

Do we have to consider solutions with multiple multiplicands?

X * Y * Z = U

?

X * Y * Z = U

?

### Re: Problem 032

NoSpura wrote:Do we have to consider solutions with multiple multiplicands?

X * Y * Z = U

?

### Re: Problem 032

No, only Multiplicand * Multiplier = ProductSpura wrote:Do we have to consider solutions with multiple multiplicands?

X * Y * Z = U

?

**Problem 32**(View Problem)