... don't post any code fragments or results ...

I think you are pushing it a bit too far jake223.

## Search found 335 matches

- Fri Jun 29, 2012 1:47 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 203
- Replies:
**4** - Views:
**2423**

- Fri Jun 22, 2012 1:08 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 227
- Replies:
**40** - Views:
**15992**

### Re: Problem 227

@aff We realize you are new to this forum. Please read the sticky post entitled "Comments, questions and clarifications about PE problems". And then, please, do not start a new topic when one already exists. Use the search box at the top of the page. An answer to your querry may already ha...

- Tue Jun 12, 2012 12:25 am
- Forum: Clarifications on Project Euler Problems
- Topic: problem 307
- Replies:
**16** - Views:
**7756**

### Re: problem 307

@sibr

Anything related to a specific Euler problem should be posted in the "Problems" forum (respecting all the recommended rules).

Anything related to a specific Euler problem should be posted in the "Problems" forum (respecting all the recommended rules).

- Mon Jun 11, 2012 4:30 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 008
- Replies:
**102** - Views:
**37474**

### Re: Problem 008

@pawanbcd We realize you are new to this forum. For problems under 100, the number is padded with leading 0's to make it a 3-digit number. This makes it easier for archiving and searching. By using this procedure, an answer to your question might already be available in previous posts. You may also ...

- Thu Jun 07, 2012 1:51 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 051
- Replies:
**60** - Views:
**29593**

### Re: Problem 051

@ghoffma1 We realize you are new to this forum. For posts related to problems, those below 100 are padded with 0's to make it a 3-digit number for ease of searching. An answer to your question may already have been posted in the past when you search the proper forum. Hope you will enjoy this site fo...

- Wed May 30, 2012 12:35 am
- Forum: Clarifications on Project Euler Problems
- Topic: problem 055
- Replies:
**31** - Views:
**12923**

### Re: problem 055

From the description of the problem: A number that never forms a palindrome through the reverse and add process is called a Lychrel number. And also: Surprisingly, there are palindromic numbers that are themselves Lychrel numbers; the first example is 4994 . Edit: Sorry TripleM for the cross-post.

- Sun May 27, 2012 4:12 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 084
- Replies:
**29** - Views:
**13689**

### Re: Problem 084

Not that it should make much of a difference, but

And, if you roll a double (unless it's the third consecutive one), the square you land on is only temporary and you continue rolling the dice.and it is the final square that the player finishes at on each roll that we are interested in

- Mon May 14, 2012 3:13 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 058
- Replies:
**32** - Views:
**13090**

### Re: Problem 058

We realize you are new to this forum. Please don't start a new thread for a problem when one already exists. For your information, problem numbers below 100 are padded with 0's to produce all 3-digit numbers for ease of searching. Your question(s) may already have been answered when you search prope...

- Sun May 06, 2012 1:23 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 023
- Replies:
**56** - Views:
**26352**

### Re: Problem 023

@CMinus Your post has been merged with the proper thread related to Problem 23. We realize you are new to this forum. Please read the sticky thread entitled "Comments, questions and clarifications about PE problems". By using the suggested search procedure, you will find that most (if not ...

- Wed May 02, 2012 4:21 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 382
- Replies:
**2** - Views:
**1827**

### Re: problem382

hopefully someone can get back to me with a decent response We can all understand your frustration (with any of the problems). However, I would strongly suggest that you refrain from using undecent language and you will hopefully edit your post accordingly. WARNING: Any other post containing such l...

- Fri Apr 27, 2012 7:57 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 016
- Replies:
**28** - Views:
**11424**

### Re: Problem 016

You would have a better idea of how this forum is expected to works by reading the first post of the sticky thread entitled "Comments, questions and clarifications about PE problems" in this Problem topic.

- Fri Apr 27, 2012 6:25 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 016
- Replies:
**28** - Views:
**11424**

### Re: Problem 016

For the simple reason that a lazy member could copy the string and then ask his program to add the digits without making any other effort to find a way to solve it.But why did you also delete the result for 2^1000?

- Fri Apr 27, 2012 3:28 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 020
- Replies:
**42** - Views:
**14539**

### Re: Problem 020

@ Dan,

You should certainly be proud of your accomplishments. However, please restrict publishing your code and results in the problem threads on the other site. This forum is NOT for that purpose.

You should certainly be proud of your accomplishments. However, please restrict publishing your code and results in the problem threads on the other site. This forum is NOT for that purpose.

- Fri Apr 27, 2012 3:16 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 016
- Replies:
**28** - Views:
**11424**

### Re: Problem 016

@ Dan

Very glad you did solve it. However, you forgot (or disregarded) the big red banner at the top of the posting page. Please read it again.

Very glad you did solve it. However, you forgot (or disregarded) the big red banner at the top of the posting page. Please read it again.

- Thu Mar 29, 2012 5:44 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 086
- Replies:
**77** - Views:
**26182**

### Re: Problem 086

Did you check where he took that list??? And the subsequent posts?????but it was included in thundre's list

- Wed Mar 28, 2012 2:02 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 345
- Replies:
**6** - Views:
**4996**

### Re: Problem 345

but unfortunately the thread is locked First, in the past, threads used to become locked only after 200 posts had been made. The thread for Problem 345 only has 145 posts at present. Secondly, threads now remain unlocked indefinitely, with the proviso that only the first 200 posts are guaranteed to...

- Thu Mar 22, 2012 3:04 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 086
- Replies:
**77** - Views:
**26182**

### Re: Problem 086

I would strongly suggest you read this thread from the start.I'm missing 665, 755, 761, and 854.

- Sat Mar 17, 2012 12:08 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 103
- Replies:
**38** - Views:
**15084**

### Re: Problem 103

As far as we know at this time, the answer is ..... NO .or is there a rule which works for all?

- Fri Mar 02, 2012 2:06 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 327
- Replies:
**8** - Views:
**4456**

### Re: Problem 327

nitpick The security card that you use to enter a room is inserted into a slot and then recycled through a complex system of conveyor belts under the floor back to the dispenser at the entrance. That's why you can't use it again. It has been removed from your possession. 8-) That complex system of ...

- Thu Feb 23, 2012 6:34 am
- Forum: Number Theory
- Topic: Even numbers and twin prime
- Replies:
**3** - Views:
**3683**

### Re: Even numbers and twin prime

2n =p*(q+1) - q*(p-1) = pq + p - pq + q = p+q

2 and 4 are the two even numbers which cannot satisfy the equation if p is allowed to be the same prime as q or q+2. Otherwise, you would have a few more even numbers.

2 and 4 are the two even numbers which cannot satisfy the equation if p is allowed to be the same prime as q or q+2. Otherwise, you would have a few more even numbers.