## Search found 544 matches

Fri Jul 24, 2020 8:37 am
Forum: News, Suggestions, and FAQ
Topic: Errors/Warnings/Bugs
Replies: 573
Views: 153250

### Re: Errors/Warnings/Bugs

Hi, I am having trouble opening the thread for Problem 497. Chrome would load a few posts but when I scrolled down further, it became just a blank screen. Maths formulas were not rendered and code sections would not open. Thank you for reporting this. I cannot load the thread either: the Chrome tab...
Tue Jun 30, 2020 2:51 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 059
Replies: 114
Views: 35510

### Re: Problem 059

Hi! I also have trouble in getting "an OK - problem solved" although I'm like TristenR am pretty sure I've solved it. However, counting up the entries in the original file - I only get 1454... which is contrary to TristenRs 1455. What is the correct number here (in the original text file)? Thanks i...
Tue Feb 25, 2020 6:32 am
Forum: Clarifications on Project Euler Problems
Topic: Problem 207
Replies: 8
Views: 4446

### Re: Problem 207

...where $4^t$, $2^t$, and $k$ are all positive integers and $t$ is a real number. For any m ≥ 1 let P(m) be the proportion of such partitions that are perfect with k ≤ m . So there are two partitions, $4^1 = 2^1 + 2$ and $4^{1.5849625...} = 2^{1.5849625...} + 6$ with $k\le 6$, only one of which ha...
Mon Feb 10, 2020 5:52 am
Forum: Clarifications on Project Euler Problems
Topic: Problem 701
Replies: 3
Views: 1638

### Re: Problem 701

701 "Consider the maximum area of connected cells." Nowhere is "maximum area" defined. It's just the literal meaning. The largest possible area of a connected set of (black) cells. Wouldn't the largest possible area be W x H, i.e. the given square with every square a black square? That is one possi...
Sun Feb 09, 2020 7:52 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 701
Replies: 3
Views: 1638

### Re: Problem 701

Junglemath wrote: Sun Feb 09, 2020 6:36 pm Problem 701 (View Problem)

"Consider the maximum area of connected cells."

Nowhere is "maximum area" defined.
It's just the literal meaning. The largest possible area of a connected set of (black) cells.
Mon Feb 03, 2020 6:49 am
Forum: Clarifications on Project Euler Problems
Topic: problem 065
Replies: 33
Views: 9061

### Re: problem 065

whatteaux wrote: Sun Feb 02, 2020 11:18 pm
jaap wrote: Fri Jan 31, 2020 12:44 pm But it is surprising that e's continued fraction has a pattern to it at all.
Did you mmean Pi, rather than e? E's has a pattern (as shown in this thread), whereas Pi's is patternless.
I'm saying that you would not expect a pattern for e, so it is surprising that there is one.
Fri Jan 31, 2020 12:44 pm
Forum: Clarifications on Project Euler Problems
Topic: problem 065
Replies: 33
Views: 9061

### Re: problem 065

In the problem statement it lists 2k as one of the components of the continued fraction, but nowhere is it stated what k is. Help? It is just there to indicate that the pattern shown in the first numbers continues. It shows what an arbitrary section of the list would look like. Here are some other ...
Fri Jan 31, 2020 9:31 am
Forum: Clarifications on Project Euler Problems
Topic: problem 065
Replies: 33
Views: 9061

### Re: problem 065

In the problem statement it lists 2k as one of the components of the continued fraction, but nowhere is it stated what k is. Help? It is just there to indicate that the pattern shown in the first numbers continues. It shows what an arbitrary section of the list would look like. Here are some other ...
Fri Dec 20, 2019 5:23 am
Forum: Clarifications on Project Euler Problems
Topic: Problem 027
Replies: 25
Views: 8501

### Re: Problem 027

If you'd care to elaborate on such a simple relationship @ PE.net, I would sure appreciate it, as I imagine Lucas-C would too... Take a look at hk's post on the first page of the problem's discussion forum. It shows the relationship between two solutions. If you plot all the related solutions (i.e....
Thu Dec 19, 2019 10:31 am
Forum: Clarifications on Project Euler Problems
Topic: Problem 027
Replies: 25
Views: 8501

### Re: Problem 027

All the solutions on a parabola are related to each other in a very simple way. Given that the solution to the problem lies on such a parabola, it would be a spoiler to discuss it too much.
Tue Dec 03, 2019 6:51 am
Forum: Clarifications on Project Euler Problems
Topic: Problem 601
Replies: 2
Views: 863

### Re: Problem 601

I disagree. $k$ is essentially the length of the streak, i.e. how many consecutive lines in the two examples have divisibility before the line where it is no longer divisible. Like a lucky streak, it is about how long you can keep it going before your luck runs out. The divisibility by 1 is part of ...
Wed Nov 20, 2019 4:19 am
Forum: Clarifications on Project Euler Problems
Topic: Problem 689
Replies: 3
Views: 1285

### Re: Problem 689

Thanks for the clarification. I'm still worried that f(x) may not be clearly defined. For example, the decimal fraction 1/2 has two binary representations: 0.1000... and 0.0111.... And those lead to f(1/2) = f(0.1000.. (base 2) ) = 1, and f(1/2) = f(0.0111.. (base 2) ) = π 2 /6 - 1. While these are...
Fri Jun 28, 2019 8:39 am
Forum: News, Suggestions, and FAQ
Topic: Errors/Warnings/Bugs
Replies: 573
Views: 153250

### Re: Errors/Warnings/Bugs

We cannot make two consecutive posts in the same solution forum. I think you should be able to edit your post and add the content in the same post. I think you misunderstood the problem. The post is not shown in the problem thread so it cannot be edited. Hopefully it is just a caching problem that ...
Thu Jun 27, 2019 10:03 am
Forum: Discrete Mathematics
Topic: The Satisfiability Problem... NP or P?!
Replies: 4
Views: 7709

### Re: The Satisfiability Problem... NP or P?!

https://medium.com/swlh/the-boolean-satisfiability-problem-solved-48ceb5550115 It is badly explained, and is certainly not a proof. It ends with: Considering that it is able to find a solution in most indices, as it usually works with a high probability (80%) then you can always try another index t...
Tue May 28, 2019 1:44 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 672
Replies: 3
Views: 5126

### Re: Problem 672

Thanks for fixing that hk. Shouldn't there be a floor function around the $\frac{7^K-1}{11}$ term? I don't think there is a universally accepted meaning for a sum where the upper limit for the index variable is not an integer. Please investigate if $\frac{7^K-1}{11}$ isn't an integer for the values ...
Tue May 28, 2019 12:35 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 672
Replies: 3
Views: 5126

### Problem 672

Is "no nothing" a typo for "do nothing"?

Shouldn't there be a floor function around the $\frac{7^K-1}{11}$ term? I don't think there is a universally accepted meaning for a sum where the upper limit for the index variable is not an integer.
Mon May 27, 2019 1:40 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 671
Replies: 3
Views: 4022

### Re: Problem 671

I have not solved this question yet, but have worked out F_4(3) on paper. @amagri: I believe those are indeed forbidden, so for both those reasons you cannot use a 1x3 tile when n=3. @MuthuVeerappanR: I think rotations around the axis of the loop are not considered different. I get 24+24+24+24+8 = 1...
Mon May 20, 2019 1:31 am
Forum: News, Suggestions, and FAQ
Topic: Recover account
Replies: 4
Views: 3854

### Re: Recover account

hk wrote: Sun May 19, 2019 12:55 pm I looked up your account:
Last Visit:

Saturday, 19th May 2018, 11:11 pm

It is 2019 now, you know.
Fri May 17, 2019 6:36 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 647
Replies: 2
Views: 3487

### Re: Problem 647

I know that quite some folk have solved this one already and it doesn't look too daunting, really - except that: well I'm getting 186 and not 184 as result for F_3(100). It really is 184. If you want, you can send me the pairs (A,B) that make up the sum by private message (you should have only four...
Sat Mar 16, 2019 8:59 pm
Forum: Clarifications on Project Euler Problems
Topic: Problem 600
Replies: 1
Views: 1264

### Re: Problem 600

RichardDL wrote: Sat Mar 16, 2019 4:13 pm 18, 5, 1, 4, 3, 3, 2
18, 5, 2, 3, 3, 4, 1
Hexagons that are mirror images of one another are congruent.