## Search found 543 matches

- Tue Jun 30, 2020 2:51 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 059
- Replies:
**114** - Views:
**30296**

### Re: Problem 059

Hi! I also have trouble in getting "an OK - problem solved" although I'm like TristenR am pretty sure I've solved it. However, counting up the entries in the original file - I only get 1454... which is contrary to TristenRs 1455. What is the correct number here (in the original text file)? Thanks i...

- Tue Feb 25, 2020 6:32 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 207
- Replies:
**8** - Views:
**3935**

### Re: Problem 207

...where $4^t$, $2^t$, and $k$ are all positive integers and $t$ is a real number. For any m ≥ 1 let P(m) be the proportion of such partitions that are perfect with k ≤ m . So there are two partitions, $4^1 = 2^1 + 2$ and $4^{1.5849625...} = 2^{1.5849625...} + 6$ with $k\le 6$, only one of which ha...

- Mon Feb 10, 2020 5:52 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 701
- Replies:
**3** - Views:
**1339**

### Re: Problem 701

701 "Consider the maximum area of connected cells." Nowhere is "maximum area" defined. It's just the literal meaning. The largest possible area of a connected set of (black) cells. Wouldn't the largest possible area be W x H, i.e. the given square with every square a black square? That is one possi...

- Sun Feb 09, 2020 7:52 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 701
- Replies:
**3** - Views:
**1339**

### Re: Problem 701

It's just the literal meaning. The largest possible area of a connected set of (black) cells.Junglemath wrote: ↑Sun Feb 09, 2020 6:36 pmProblem 701(View Problem)

"Consider the maximum area of connected cells."

Nowhere is "maximum area" defined.

- Mon Feb 03, 2020 6:49 am
- Forum: Clarifications on Project Euler Problems
- Topic: problem 065
- Replies:
**33** - Views:
**7596**

### Re: problem 065

I'm saying that you would not expect a pattern for e, so it is surprising that there is one.

- Fri Jan 31, 2020 12:44 pm
- Forum: Clarifications on Project Euler Problems
- Topic: problem 065
- Replies:
**33** - Views:
**7596**

### Re: problem 065

In the problem statement it lists 2k as one of the components of the continued fraction, but nowhere is it stated what k is. Help? It is just there to indicate that the pattern shown in the first numbers continues. It shows what an arbitrary section of the list would look like. Here are some other ...

- Fri Jan 31, 2020 9:31 am
- Forum: Clarifications on Project Euler Problems
- Topic: problem 065
- Replies:
**33** - Views:
**7596**

### Re: problem 065

In the problem statement it lists 2k as one of the components of the continued fraction, but nowhere is it stated what k is. Help? It is just there to indicate that the pattern shown in the first numbers continues. It shows what an arbitrary section of the list would look like. Here are some other ...

- Fri Dec 20, 2019 5:23 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 027
- Replies:
**25** - Views:
**7390**

### Re: Problem 027

If you'd care to elaborate on such a simple relationship @ PE.net, I would sure appreciate it, as I imagine Lucas-C would too... Take a look at hk's post on the first page of the problem's discussion forum. It shows the relationship between two solutions. If you plot all the related solutions (i.e....

- Thu Dec 19, 2019 10:31 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 027
- Replies:
**25** - Views:
**7390**

### Re: Problem 027

All the solutions on a parabola are related to each other in a very simple way. Given that the solution to the problem lies on such a parabola, it would be a spoiler to discuss it too much.

- Tue Dec 03, 2019 6:51 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 601
- Replies:
**2** - Views:
**592**

### Re: Problem 601

I disagree. $k$ is essentially the length of the streak, i.e. how many consecutive lines in the two examples have divisibility before the line where it is no longer divisible. Like a lucky streak, it is about how long you can keep it going before your luck runs out. The divisibility by 1 is part of ...

- Wed Nov 20, 2019 4:19 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 689
- Replies:
**3** - Views:
**971**

### Re: Problem 689

Thanks for the clarification. I'm still worried that f(x) may not be clearly defined. For example, the decimal fraction 1/2 has two binary representations: 0.1000... and 0.0111.... And those lead to f(1/2) = f(0.1000.. (base 2) ) = 1, and f(1/2) = f(0.0111.. (base 2) ) = π 2 /6 - 1. While these are...

- Fri Jun 28, 2019 8:39 am
- Forum: News, Suggestions, and FAQ
- Topic: Errors/Warnings/Bugs
- Replies:
**539** - Views:
**128851**

### Re: Errors/Warnings/Bugs

We cannot make two consecutive posts in the same solution forum. I think you should be able to edit your post and add the content in the same post. I think you misunderstood the problem. The post is not shown in the problem thread so it cannot be edited. Hopefully it is just a caching problem that ...

- Thu Jun 27, 2019 10:03 am
- Forum: Discrete Mathematics
- Topic: The Satisfiability Problem... NP or P?!
- Replies:
**4** - Views:
**6190**

### Re: The Satisfiability Problem... NP or P?!

https://medium.com/swlh/the-boolean-satisfiability-problem-solved-48ceb5550115 It is badly explained, and is certainly not a proof. It ends with: Considering that it is able to find a solution in most indices, as it usually works with a high probability (80%) then you can always try another index t...

- Tue May 28, 2019 1:44 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 672
- Replies:
**3** - Views:
**4825**

### Re: Problem 672

Thanks for fixing that hk. Shouldn't there be a floor function around the $\frac{7^K-1}{11}$ term? I don't think there is a universally accepted meaning for a sum where the upper limit for the index variable is not an integer. Please investigate if $\frac{7^K-1}{11}$ isn't an integer for the values ...

- Tue May 28, 2019 12:35 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 672
- Replies:
**3** - Views:
**4825**

### Problem 672

Is "no nothing" a typo for "do nothing"?

Shouldn't there be a floor function around the $\frac{7^K-1}{11}$ term? I don't think there is a universally accepted meaning for a sum where the upper limit for the index variable is not an integer.

Shouldn't there be a floor function around the $\frac{7^K-1}{11}$ term? I don't think there is a universally accepted meaning for a sum where the upper limit for the index variable is not an integer.

- Mon May 27, 2019 1:40 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 671
- Replies:
**3** - Views:
**3732**

### Re: Problem 671

I have not solved this question yet, but have worked out F_4(3) on paper. @amagri: I believe those are indeed forbidden, so for both those reasons you cannot use a 1x3 tile when n=3. @MuthuVeerappanR: I think rotations around the axis of the loop are not considered different. I get 24+24+24+24+8 = 1...

- Mon May 20, 2019 1:31 am
- Forum: News, Suggestions, and FAQ
- Topic: Recover account
- Replies:
**4** - Views:
**3508**

- Fri May 17, 2019 6:36 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 647
- Replies:
**2** - Views:
**3278**

### Re: Problem 647

I know that quite some folk have solved this one already and it doesn't look too daunting, really - except that: well I'm getting 186 and not 184 as result for F_3(100). It really is 184. If you want, you can send me the pairs (A,B) that make up the sum by private message (you should have only four...

- Sat Mar 16, 2019 8:59 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 600
- Replies:
**1** - Views:
**1062**

- Wed Mar 06, 2019 4:21 pm
- Forum: News, Suggestions, and FAQ
- Topic: Project Euler Style Sheet Update
- Replies:
**33** - Views:
**12132**

### Re: Project Euler Style Sheet Update

First, I don't know how to switch from the dark theme to light or vice versa. Is this missing, hidden, or am I just blind? In the Account tab, there is a section with Country, Language etc, including Theme. Change the Theme from Dark to Default (and click the Update Details button) to go back to wh...