Did you mmean Pi, rather than e? E's has a pattern (as shown in this thread), whereas Pi's is patternless.

## Search found 7 matches

- Sun Feb 02, 2020 11:18 pm
- Forum: Clarifications on Project Euler Problems
- Topic: problem 065
- Replies:
**33** - Views:
**13226**

- Mon Aug 19, 2019 2:25 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 114
- Replies:
**12** - Views:
**5671**

- Sun Mar 05, 2017 11:18 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 148
- Replies:
**16** - Views:
**8303**

### Re: Problem 148

As you have guessed, the problem is almost certainly something to do with numerical accuracy with the higher numbers. I don't use python much, so can't help you much with number storage limitations and overflows in that language, but that is likely to be the area to look at. Firstly, Python has no ...

- Mon Jan 09, 2017 12:11 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 129
- Replies:
**13** - Views:
**6095**

### Re: Problem 129

The problem requires that GCD(n,1) = 1, but GCD(16,10) != 1, so we shouldn't be considering n = 16 at all. That's why the first relevant value is 17 - GCD(17,10) = 1.

- Mon Oct 19, 2015 1:06 am
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 177
- Replies:
**26** - Views:
**17278**

### Re: Problem 177

It is easy to see how to generalise this get all 45 solutions that are a kite and cyclic. I'm also struggling with this one (but have too many, not too few!). Cyclic? Why cyclic? For example, how about a quad with angles {8,170,1,4,5,86,85,1} which meets the requirements but isn't cyclic? Or {30,30...

- Fri Sep 25, 2015 1:29 am
- Forum: Number Theory
- Topic: Set of natural numbers
- Replies:
**2** - Views:
**7576**

### Re: Set of natural numbers

So you want someone to just hand you the answer to problem 142, do you?

- Thu Nov 22, 2012 10:01 pm
- Forum: Clarifications on Project Euler Problems
- Topic: Problem 187
- Replies:
**9** - Views:
**5282**

### Re: Problem 187

If your idea is based on counting semi-primes, it's probably wrong. 12 is not a semi-prime, but it does have exactly 2 prime factors. This makes it even more confusing. The title of the problem is "Semi-primes" (the text that pops up when I hover over it in the 'progress' view). In the ex...