Project Euler Forum

Thanks Jaap.
I made it: Calculate the sum of $H_{100}(\sqrt \beta)$ for $\beta \in T$.

I sent you a PM.

Perhaps you registered as marksquall and later renamed your account to what it is called now?

When I look up the account marksquall there are no solved problems, and the user ID is 1441140.
What user ID does your marksquall account have?

Accounts are not being deleted because of inactivity.
Perhaps you don't remember the (previous) username correctly.

It's the way it is intended.
If you go to the main statistics page and switch to "view data for active members only" you can view the active Python members.

Look up your account. Perhaps it has been set to unlisted.

Could it be that your bruteforcer is wrong?

As you can see Fastest Solvers Table and overview are in sync now. The solve count is cached on the site. It's not updated until someone solves the problem or an admin views who solved this problem. Even then the overview page is cached so the updated count is only showed when the overview page is r...

After several failed attempts at solving this problem, i decided to look for the answer somewhere. It appears to me that I found some other solutions that are not stated on the answer given. I double checked and still I think my solutions include more pandigital products. There might be some wordin...

Could you try another browser?
With me the problem turns up in IE11, but not in Chrome or Firefox. (With seemingly random pages. By me the page affected behaved normal again after about 48 hours)
Please let us know the result.

You generated your recovery key on Sat, 25 Mar 2017, 23:56.30.
The only way to recover your account is to find back this key. I assume that you saved it somewhere.
If you don't find it back, your account is lost.

Does the problem persist?

It should read $1\le p\lt q\le n$. Problem edited.

Squaring a matrix has nothing to do with matrix addition.
What you can read there is that for some matrices A,B,C holds that $A=B^2$ but also $A=C^2$

If you want to go up to 5 you have to concatenate 2469*1 and 2469*2 and 2469*3 and 2469*4 and 2469*5.
This gives 246949387407987612345

mdean wrote: ↑

Tue Nov 06, 2018 5:55 pm

I think I have some idea how to approach this problem, but I am completely lost by this thread, which seems to bear no resemblance to anything in problem 641...

Nothing is left in this thread to get lost.

The alternative account could have been creyD_
That one has solved one more problem than creyD has solved now. The problems solved by creyD were also solved by creyD_.

Please read the provided pdf write-up on the main site. (click on the pdf-icon)
Hint: you can use the formula for the sum of an arithmetic sequence. https://en.wikipedia.org/wiki/Arithmetic_progression

Vamsi, could you please stop throwing hints around?
People should be able to browse this board without fear for unwanted hints.